Today we will learn how to multiply two numbers having first digits same and sum of second digits is 10 using Vedic Mathematics methods.
Let's understand it through examples.
Example 1: 47*43
Here first digits are same, i.e. 4. Sum of second digits is 7 + 3 = 10.
This is exactly the conditions we are talking.
How to find the multiplication result:
Multiply 4 by 4+1, i.e. 4*(4+1)=20
Multiply last two digits, i.e. 7*3 = 21
Now the result is, 47 * 43 = [4*(4+1)][7*3]=[20][21]=2021
Example 2: 52*58
52*58 = [5*(5+1)][2*8] = [30][16]=3016
Example 3: 84*86
84*86 = [8*(8+1)][4*6] = [72][24]=7224
Example 4: 75*75
75*75 = [7*(7+1)][5*5] = [56][25]=5625
Example 5: 69*61
69*61 = [6*(6+1)][9*1] = [42][09]=4209
Note that in this example, we had to add 0 to make second part a two digit number.
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